Integrand size = 11, antiderivative size = 56 \[ \int \frac {(a+b x)^6}{x^{10}} \, dx=-\frac {(a+b x)^7}{9 a x^9}+\frac {b (a+b x)^7}{36 a^2 x^8}-\frac {b^2 (a+b x)^7}{252 a^3 x^7} \]
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Time = 0.01 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {47, 37} \[ \int \frac {(a+b x)^6}{x^{10}} \, dx=-\frac {b^2 (a+b x)^7}{252 a^3 x^7}+\frac {b (a+b x)^7}{36 a^2 x^8}-\frac {(a+b x)^7}{9 a x^9} \]
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Rule 37
Rule 47
Rubi steps \begin{align*} \text {integral}& = -\frac {(a+b x)^7}{9 a x^9}-\frac {(2 b) \int \frac {(a+b x)^6}{x^9} \, dx}{9 a} \\ & = -\frac {(a+b x)^7}{9 a x^9}+\frac {b (a+b x)^7}{36 a^2 x^8}+\frac {b^2 \int \frac {(a+b x)^6}{x^8} \, dx}{36 a^2} \\ & = -\frac {(a+b x)^7}{9 a x^9}+\frac {b (a+b x)^7}{36 a^2 x^8}-\frac {b^2 (a+b x)^7}{252 a^3 x^7} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.43 \[ \int \frac {(a+b x)^6}{x^{10}} \, dx=-\frac {a^6}{9 x^9}-\frac {3 a^5 b}{4 x^8}-\frac {15 a^4 b^2}{7 x^7}-\frac {10 a^3 b^3}{3 x^6}-\frac {3 a^2 b^4}{x^5}-\frac {3 a b^5}{2 x^4}-\frac {b^6}{3 x^3} \]
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Time = 0.04 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.21
method | result | size |
norman | \(\frac {-\frac {1}{3} b^{6} x^{6}-\frac {3}{2} a \,x^{5} b^{5}-3 a^{2} x^{4} b^{4}-\frac {10}{3} a^{3} x^{3} b^{3}-\frac {15}{7} a^{4} x^{2} b^{2}-\frac {3}{4} a^{5} x b -\frac {1}{9} a^{6}}{x^{9}}\) | \(68\) |
risch | \(\frac {-\frac {1}{3} b^{6} x^{6}-\frac {3}{2} a \,x^{5} b^{5}-3 a^{2} x^{4} b^{4}-\frac {10}{3} a^{3} x^{3} b^{3}-\frac {15}{7} a^{4} x^{2} b^{2}-\frac {3}{4} a^{5} x b -\frac {1}{9} a^{6}}{x^{9}}\) | \(68\) |
gosper | \(-\frac {84 b^{6} x^{6}+378 a \,x^{5} b^{5}+756 a^{2} x^{4} b^{4}+840 a^{3} x^{3} b^{3}+540 a^{4} x^{2} b^{2}+189 a^{5} x b +28 a^{6}}{252 x^{9}}\) | \(69\) |
default | \(-\frac {10 a^{3} b^{3}}{3 x^{6}}-\frac {15 a^{4} b^{2}}{7 x^{7}}-\frac {a^{6}}{9 x^{9}}-\frac {b^{6}}{3 x^{3}}-\frac {3 a \,b^{5}}{2 x^{4}}-\frac {3 a^{2} b^{4}}{x^{5}}-\frac {3 a^{5} b}{4 x^{8}}\) | \(69\) |
parallelrisch | \(\frac {-84 b^{6} x^{6}-378 a \,x^{5} b^{5}-756 a^{2} x^{4} b^{4}-840 a^{3} x^{3} b^{3}-540 a^{4} x^{2} b^{2}-189 a^{5} x b -28 a^{6}}{252 x^{9}}\) | \(69\) |
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Time = 0.21 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.21 \[ \int \frac {(a+b x)^6}{x^{10}} \, dx=-\frac {84 \, b^{6} x^{6} + 378 \, a b^{5} x^{5} + 756 \, a^{2} b^{4} x^{4} + 840 \, a^{3} b^{3} x^{3} + 540 \, a^{4} b^{2} x^{2} + 189 \, a^{5} b x + 28 \, a^{6}}{252 \, x^{9}} \]
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Time = 0.27 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.30 \[ \int \frac {(a+b x)^6}{x^{10}} \, dx=\frac {- 28 a^{6} - 189 a^{5} b x - 540 a^{4} b^{2} x^{2} - 840 a^{3} b^{3} x^{3} - 756 a^{2} b^{4} x^{4} - 378 a b^{5} x^{5} - 84 b^{6} x^{6}}{252 x^{9}} \]
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Time = 0.19 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.21 \[ \int \frac {(a+b x)^6}{x^{10}} \, dx=-\frac {84 \, b^{6} x^{6} + 378 \, a b^{5} x^{5} + 756 \, a^{2} b^{4} x^{4} + 840 \, a^{3} b^{3} x^{3} + 540 \, a^{4} b^{2} x^{2} + 189 \, a^{5} b x + 28 \, a^{6}}{252 \, x^{9}} \]
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Time = 0.29 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.21 \[ \int \frac {(a+b x)^6}{x^{10}} \, dx=-\frac {84 \, b^{6} x^{6} + 378 \, a b^{5} x^{5} + 756 \, a^{2} b^{4} x^{4} + 840 \, a^{3} b^{3} x^{3} + 540 \, a^{4} b^{2} x^{2} + 189 \, a^{5} b x + 28 \, a^{6}}{252 \, x^{9}} \]
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Time = 0.10 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.21 \[ \int \frac {(a+b x)^6}{x^{10}} \, dx=-\frac {\frac {a^6}{9}+\frac {3\,a^5\,b\,x}{4}+\frac {15\,a^4\,b^2\,x^2}{7}+\frac {10\,a^3\,b^3\,x^3}{3}+3\,a^2\,b^4\,x^4+\frac {3\,a\,b^5\,x^5}{2}+\frac {b^6\,x^6}{3}}{x^9} \]
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